10+3[4+3(x-2)]=3-(x-1)

Solution for 10+3[4+3(x-2)]=3-(x-1) equation:

Simplifying
10 + 3[4 + 3(x + -2)] = 3 + -1(x + -1)

Reorder the terms:
10 + 3[4 + 3(-2 + x)] = 3 + -1(x + -1)
10 + 3[4 + (-2 * 3 + x * 3)] = 3 + -1(x + -1)
10 + 3[4 + (-6 + 3x)] = 3 + -1(x + -1)

Combine like terms: 4 + -6 = -2
10 + 3[-2 + 3x] = 3 + -1(x + -1)
10 + [-2 * 3 + 3x * 3] = 3 + -1(x + -1)
10 + [-6 + 9x] = 3 + -1(x + -1)

Combine like terms: 10 + -6 = 4
4 + 9x = 3 + -1(x + -1)

Reorder the terms:
4 + 9x = 3 + -1(-1 + x)
4 + 9x = 3 + (-1 * -1 + x * -1)
4 + 9x = 3 + (1 + -1x)

Combine like terms: 3 + 1 = 4
4 + 9x = 4 + -1x

Add '-4' to each side of the equation.
4 + -4 + 9x = 4 + -4 + -1x

Combine like terms: 4 + -4 = 0
0 + 9x = 4 + -4 + -1x
9x = 4 + -4 + -1x

Combine like terms: 4 + -4 = 0
9x = 0 + -1x
9x = -1x

Solving
9x = -1x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add 'x' to each side of the equation.
9x + x = -1x + x

Combine like terms: 9x + x = 10x
10x = -1x + x

Combine like terms: -1x + x = 0
10x = 0

Divide each side by '10'.
x = 0.0

Simplifying
x = 0.0